2 a 8,5:3=2,8(3) b.18,7:6=3,11(6) c.58:11=5,(27) d.14,2:3,33=4,(264)

3a.0,32=8/25 b.-0,124=-31/250 c1,28=32/25 d,-3,12=-78/25

4

1/99=0.(01) 1/999=0,(001)

đúng thì tích nha

hellooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo mấy dứa dở

Helllooooooooooooooooi you khedive have 

Câu 1:

MSC=60

7/10=7.6/10.6=42/60            5/-12=-5/12=-5.5/12.5=-25/60

Câu 2:

17/34=1/2;  -12/22=-6/11;  -25/35=-5/7;  125/75=5/3

Câu 3:

MSC=24

1/3=1.8/3.8=8/24     -3/8=-3.3/8.3=-9/24           17/24=17/24

a. 3 : 11 = \(\dfrac{3}{11}\)

b. -4 : 7 = \(\dfrac{-4}{7}\)

c 5 : ( -13)  = \(\dfrac{5}{-13}=\dfrac{-5}{13}\)

d x : 3 \(\left(x\in z\right)\)

= \(\dfrac{x}{3}\)

\(a,3:11=\dfrac{3}{11}=\dfrac{-3}{-11}\\ b,-4:7=\dfrac{-4}{7}=\dfrac{4}{-7}\\ c,5:\left(-13\right)=\dfrac{5}{-13}=\dfrac{-5}{13}\\ d,x:3=\dfrac{x}{3}=\dfrac{-x}{-3}\)

a ) 7 10 . b ) 1 − 5 . c ) − 2 5 . d ) − 2 − 3 .

c: \(=\dfrac{x^3+2x+2x^2+2x+x^2-x+1}{\left(x+1\right)\left(x^2-x+1\right)}\)

\(=\dfrac{x^3+3x^2+3x+1}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{x^2+2x+1}{x^2-x+1}\)

\(a,3:11=\frac{3}{11}\)

\(b,-4:7=\frac{-4}{7}\)

\(c,5:\left(-13\right)=\frac{5}{-13}=\frac{-5}{13}\)

\(d,x:3=\frac{x}{3}\)

a) \(\frac{3}{11}\)

b) \(\frac{-4}{7}\)

c) \(\frac{5}{-13}\)

d)    \(\frac{x}{3}\)

a) 3 : 11 = \(\frac{3}{11}\)

b) -4 : 7 = \(\frac{-4}{7}\)

c) 5 : (-13) = \(\frac{-5}{13}\)

d) x : 3 = \(\frac{x}{3}\)

a  3 : 11 = 3/11   b  -4 : 7 = -4/7    c   x : 3 = x/3

\(\frac{3}{11}\)

\(\frac{-4}{7}\)

\(\frac{x}{3}\)

a ) 9 13 b ) 11 − 5 c ) − 4 11 . d ) − 2 − 13 .